Physics ENERGY CONSIDERATION: A QUANTITATIVE STUDY, EDDY CURRENTS FOR CBSE-NCERT

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`color{blue}{star}` ENERGY CONSIDERATION : A QUANTITATIVE STUDY
`color{blue}{star}` EDDY CURRENTS

ENERGY CONSIDERATION: A QUANTITATIVE STUDY

`color{blue} ✍️`In Section 6.5, we discussed qualitatively that Lenz’s law is consistent with the law of conservation of energy. Now we shall explore this aspect further with a concrete example.

`color{blue} ✍️`Let `r` be the resistance of movable arm `PQ` of the rectangular conductor shown in Fig. 6.10. We assume that the remaining arms `QR, RS` and `SP` have negligible resistances compared to r. Thus, the overall resistance of the rectangular loop is `r` and this does not change as `PQ` is moved. The current `I` in the loop is,

`color{blue}(I = ε/r)`

`color{blue}(=(Blv)/r)`

..............(6.7)

`color{blue} ✍️` On account of the presence of the magnetic field, there will be a force on the arm PQ. This force `I (l × B),` is directed outwards in the direction opposite to the velocity of the rod. The magnitude of this force is,

`color{blue}(F = I lB= (B^2l^2v)/r)`




`color {blue}(➢➢}`where we have used Eq. (6.7).

`color{brown} bbul{"Note that"}` this force arises due to drift velocity of charges (responsible for current) along the rod and the consequent Lorentz force acting on them. Alternatively, the arm `PQ` is being pushed with a constant speed `v`, the power required to do this is,

`color{blue}(P = Fv)`

`color{blue}(=(B^2l^2v)/r)`

............................(6.8)

`color{blue} ✍️`The agent that does this work is mechanical. Where does this mechanical energy go? The answer is: it is dissipated as Joule heat, and is given by

`color{blue}(P_j = I^2r = ((Blu)/r)^2 r = (B^2l^2v)/r)`

which is identical to Eq. (6.8).

`color {blue}{➢➢}` Thus, mechanical energy which was needed to move the arm `PQ` is converted into electrical energy (the induced emf) and then to thermal energy. There is an interesting relationship between the charge flow through the circuit and the change in the magnetic flux. From Faraday’s law, we have learnt that the magnitude of the induced emf is,

`color{blue}(|ε| = (DeltaΦ_B)/(Deltat))`



`color {blue}{➢➢}`However,

`color{blue}(|ε| =Ir (DeltaΦ_B)/(Deltat)r)`

`color {blue}{➢➢}`Thus,

`color{blue}(DeltaQ= (DeltaΦ_B)/r)`


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Refer to Fig. 6.12(a). The arm `PQ` of the rectangular conductor is moved from `x = 0,` outwards. The uniform magnetic field is perpendicular to the plane and extends from `x = 0` to `x = b` and is zero for `x > b.` Only the arm PQ possesses substantial resistance r. Consider the situation when the arm PQ is pulled outwards from `x = 0` to `x = 2b,` and is then moved back to `x = 0` with constant speed `v`. Obtain expressions for the flux, the induced emf, the force necessary to pull the arm and the power dissipated as Joule heat. Sketch the variation of these quantities with distance.
Class 12 Chapter 6 Example 8
Solution:

Let us first consider the forward motion from `x = 0` to `x = 2b` The flux `Φ_B` linked with the circuit SPQR is

`color {blue}{Φ_B = Blx} " "0 ≤ x < b`

`color {blue}{= Bl b }" " b ≤ x < 2b`

`color {blue}{ε = - (dΦ_B)/(dt)}`

`color {blue}{= - Blv}" " 0 ≤ x < b`

`color {blue}{= 0 }" "b ≤ x <2b`

When the induced emf is non-zero, the current `I` is (in magnitude)

`color {blue}{I = (Blv)/r}`

The force required to keep the arm PQ in constant motion is I lB. Its direction is to the left. In magnitude

`color {blue}{F = (B^2l^2v)/r} " "0 ≤ x < b`

`color {blue}{= 0 }" "b ≤ x <2b`

The Joule heating loss is

`color {blue}{P_J = I^2 r}`

`color {blue}{= (B^2l^2v)/r} " "0 ≤ x < b`

`color {blue}{= 0 }" "b ≤ x <2b`

One obtains similar expressions for the inward motion from `color {blue}{x = 2b}` to `color {blue}{x = 0}.` One can appreciate the whole process by examining the sketch of various quantities displayed in Fig. 6.12(b).

EDDY CURRENTS

`color{blue} ✍️` As we know electric currents induced in well defined paths in conductors like circular loops. Even when bulk pieces of conductors are subjected to changing magnetic flux, induced currents are produced in them.
However, their flow patterns resemble swirling eddies in water. This effect was discovered by physicist Foucault (1819-1868) and these currents are called eddy currents.

`color{blue} ✍️` Consider the apparatus shown in Fig. 6.13. A copper plate is allowed to swing like a simple pendulum between the pole pieces of a strong magnet. It is found that the motion is damped and in a little while the plate comes to a halt in the magnetic field.
We can explain this phenomenon on the basis of electromagnetic induction. Magnetic flux associated with the plate keeps on changing as the plate moves in and out of the region between magnetic poles.

`color{blue} ✍️` The flux change induces eddy currents in the plate. Directions of eddy currents are opposite when the plate swings into the region between the poles and when it swings out of the region.



`color{blue} ✍️` If rectangular slots are made in the copper plate as shown in Fig. 6.14, area available to the flow of eddy currents is less. Thus, the pendulum plate with holes or slots reduces electromagnetic damping and the plate swings more freely.

`color{blue} bbul{"Note that"}` magnetic moments of the induced currents (which oppose the motion) depend upon the area enclosed by the currents (recall equation `m = IA` in Chapter 4).



`color {blue}➢` This fact is helpful in reducing eddy currents in the metallic cores of transformers, electric motors and other such devices in which a coil is to be wound over metallic core.
Eddy currents are undesirable since they heat up the core and dissipate electrical energy in the form of heat. Eddy currents are minimised by using laminations of metal to make a metal core.
The laminations are separated by an insulating material like lacquer. The plane of the laminations must be arranged parallel to the magnetic field, so that they cut across the eddy current paths. This arrangement reduces the strength of the eddy currents. Since the dissipation of electrical energy into heat depends on the square of the strength of electric current, heat loss is substantially reduced.


`color {blue}{➢➢}`Eddy currents are used to advantage in certain applications like:
`color {blue}{(i)}` Magnetic braking in trains: Strong electromagnets are situated above the rails in some electrically powered trains.
When the electromagnets are activated, the eddy currents induced in the rails oppose the motion of the train. As there are no mechanical linkages, the braking effect is smooth.

`color {blue}{(ii)}` Electromagnetic damping: Certain galvanometers have a fixed core made of nonmagnetic metallic material. When the coil oscillates, the eddy currents generated in the core oppose the motion and bring the coil to rest quickly.

`color {blue}{(iii)}` Induction furnace: Induction furnace can be used to produce high temperatures and can be utilised to prepare alloys, by melting the constituent metals.
A high frequency alternating current is passed through a coil which surrounds the metals to be melted. The eddy currents generated in the metals produce high temperatures sufficient to melt it.

`color {blue}{(iv)}` Electric power meters: The shiny metal disc in the electric power meter (analogue type) rotates due to the eddy currents. Electric currents are induced in the disc by magnetic fields produced by sinusoidally varying currents in a coil. You can observe the rotating shiny disc in the power meter of your house.

 
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