Q 1481601527.     Calculate the electronegativity of Flourine, given the following: `E_{H-H} = 104.2 kcal mol^{-1}, E_{F-F} = 36.6 kcal mol^{-1}, E_{H-F} = 134.6 kcal mol^{-1}, chi_H = 2.1`

A

`3.766`

B

`3.98`

C

`3.543`

D

`3.666`

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