Q 1619445319.     lf f(x)=\begin{cases}-x- \frac{\pi }{2}, & \text{ } x \le - \frac{\pi }{2} \\ - cos x, & \text{ } - \frac{\pi }{2} < x \le 0 \\ x-1, & \text{} 0 < x \le 1 \\ lnx, & \text{ } x>1 \end{cases} then

JEE 2011 ADVANCED Paper - 2

(This question may have multiple correct answers)

A f(x) ls contlnuous at `x=- \frac{\pi}{2}`
B f(x) is not differentiable at x=0
C f(x) is differentiable at x=1
D f(x) is differentiable at `x=- \frac{3}{2}`

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