Q 1386780677.     General solution of differential equation : `x^2e^y dy - (x-1) e^x dx=0`

A

`e^x=frac{e^y}{x}+c`

B

`e^y=frac{e^x}{x}+c`

C

`e^x= frac{e^y}{y}+c`

D

`e^y= frac{e^x}{y}+c`

HINT

separating the variable we can written as `d(e^y)= d ( frac{e^x}{x})`

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