Q .     A block `A` of mass `m_1` rests on a horizontal table. A light string connected to it passes over a frictionless pulley at the edge of table and from its other end another block `B` of mass `m_2` is suspended. the coefficient of kinetic friction between the block and the table is `\mu_k`. When the block `A` is sliding on the table, the tension in the string is:

AIPMT 2015
A

`\frac {m_1m_2(1+\mu_k)g}{(m_1+m_2)}`

B

`\frac {m_1m_2(1-\mu_k)g}{(m_1+m_2)}`

C

`\frac {(m_2+\mu_k m_1)g}{(m_1+m_2)}`

D

`\frac {(m_2-\mu_k m_1)g}{(m_1+m_2)}`

HINT

The blocks `m_1` and `m_2` will move with combined acceleration `a` `T=m_2g-m_2a` (From free body diagram)

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