Q 1619534419.     A long insulated copper wire is closely wound as a spiral of 'N' turns. The spiral has inner radius ` a' and outer radius 'b'. The spiral lies in the X-Y plane and a steady current 'I' flows through the wire. The Z-component of the magnetic field at the center of the spiral is

JEE 2011 ADVANCED Paper - 2
A

` \frac{\mu_{0}NI}{2(b-a)}\ln(\frac{b}{a})`

B

` \frac{\mu_{0}NI}{2(b-a)}\ln(\frac{b+a}{b-a})`

C

`\frac{\mu_{0}NI}{2b}\ln(\frac{b}{a})`

D

` \frac{\mu_{0}NI}{2b}\ln(\frac{b+a}{b-a})`

HINT

Magnetic field `=\int_a^b \ \frac{\mu_{o}IN}{2r(b-a)} dr `

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