Q 1119823719.     Calculate equilibrium constant of the following reaction

`CN^(-) + CH_3COOH -> HCN + CH_3COO^(-)`

`(K_b(CN^-) = 2.04 × 10^(-5), K_b(CH_3COO^-) = 5.55 × 10^(-10)`

A

`6.24 × 10^4`

B

`3.68 × 10^4`

C

`4.23 × 10^4`

D

`5.93 × 10^4`

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