Q 1220080811.     `0.400` g of an acid `HA (`mol. mass `= 80)` was dissolved in `100`g of water. The solution showed a depression of freezing point of ` 0.12` K. Calculate the dissociation constant of the acid at about `0°C`, given `K`(water) = `1.86` K Kg `mol^(–1).` Assume molarity of solution ≈ molality

A

`5.08 xx 10^(-4)`

B

`4.18 xx 10^(-4)`

C

`6.71 xx 10^(-3)`

D

`5.92 xx 10^(-3)`

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