Q 1224034851.     Let the distance between the plane `Ax - 2y + z = d` and the plane containing the lines `(x−1)/2 = (y−2)/3 = (z−3)/4` and `(x−2)/3 = (y−3)/4 = (z−4)/5` be `√6` , then `| d |` is…….

JEE 1985
A

`6`

B

`8`

C

`7`

D

`5`

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