Q 1280580417.     `13.44 g` of freshly prepared `CuCl_2` are added to one kilogram of water, the elevation in boiling point is.

[Given, `K_b = 0.52 kg K mol^(–1)`, molecular weight of `CuCl_2=134.4g mol^(-1)`].

JEE-MIS
A

`0.05`

B

`0.16`

C

`0.1`

D

`0.21`

HINT

Use formula: `ΔT_b = iK_b m`

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