Q 1307323288.     If the vertices of a triangle are `A(1,4,2), B(-2,1,2) C(2,-3,4)` then the angle `B = `?

A

`cos^{-1}frac{sqrt 6}{3}`

B

`cos^{-1} frac{1}{sqrt 3}`

C

`90^{circ}`

D

`cos^{-1}sqrt 3`

HINT

Angle ` B` is given by `cos^{-1}(frac{vec {BA}.vec {BC}}{|vec {BA}||vec {BC}|})`

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