Q 2167501485.     The extremities of a diameter of a sphere lie on positive `y`
and positive `z`-axes at distances `2` and `4` from the origin,
respectively, then

A

sphere passes through the origin

B

centre of the sphere is `(0, 1, 2)`

C

radius of the sphere is `sqrt (5)`

D

equation of a diameter is `x/0 = (y-2)/1 = (z-4)/-2`

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