Q 2261301225.     If `hat(i) xx ( vec(r) xx hat(i) ) + hat(j) xx ( vec(r) xx hat(j) ) + hat(k) xx ( vec(r) xx hat(k))`

`= vec(a) xx vec(b) ( vec(a) ne 0, vec(b) ne 0 )`, then

A

`vec(r) = vec(a) xx vec(b)`

B

`vec(r) = (vec(a) xx vec(b))/2`

C

` vec(r) = vec(0)`

D

None of these

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