Q 2613723649.     Three solutions are prepared by adding 'w' gm of 'A' into 1 kg of water, 'w' gm of 'B' into another 1 kg of water and 'w' gm . of 'C' in another 1 kg of water (A, B, C are non electrolytic). Dry air is passed from these solutions in sequence `(A -> B -> C)`. The loss in weight of solution A was found to be 2 gm while solution B gained 0.5 gm and solution C lost 1 gm. Then the relation between molar masses of A, B and C is :

A

`M_A : M_B : M_C = 4 : 3 : 5`

B

`M_A : M_B : M_C = 1/4 : 1/3 : 1/5`

C

`M_C > M_A > M_B`

D

`M_B > M_A > M_C`

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