Q 2636723672.     A sample of `AgCl` was treated with `5.00` mL of `1.5` M `Na_2CO_3` solution to give `Ag _2CO_3`. The remaining solution contained `0.0026` g of `Cl^(-)` ions per litre. Calculate the solubility product of `AgCl. [K_(sp) (Ag_ 2CO_3 ) = 8.2 xx 10^(-12)]`

JEE 1997
A

`6 xx 10^(-8)`

B

`4 xx 10^(-8)`

C

`9 xx 10^(-8)`

D

`2 xx 10^(-8)`

Find instant solution to any question from our database of 1.5 Lakh + Questions

 

Access free resources including

Engineering

Medical

Banking

DEFENCE

SSC

RRB

CBSE-NCERT

OLYMPIAD

Today's Score

0
Success Rate: NAN %

Practice & Test

Sr. No.SubjectTagCorrectRecorded Answer