Q 2646867773.     (a) The conductivity of 0.001 mol `L^-1` solution of `CH_3COOH` is `3.905 × 10^-5` S `cm^-1`. Calculate its molar conductivity and degree of dissociation (`α`)

Given `λ°(H^+ )= 349.6 S cm^2 mo^l-1` and `λ°(CH_3COO^- )= 40.9 S cm^2mol^-1`.

(b) Define electrochemical cell. What happens if external potential applied becomes greater than `E_(cell)^°` of electrochemical cell?

CBSE-12th 2016

Find instant solution to any question from our database of 1.5 Lakh + Questions

 

Access free resources including

Engineering

Medical

Banking

DEFENCE

SSC

RRB

CBSE-NCERT

OLYMPIAD

Today's Score

0
Success Rate: NAN %

Practice & Test

Sr. No.SubjectTagCorrectRecorded Answer