Q 2652367234.     During an electrolysis of cone. `H_2SO_4`, perdisulphuric acid `(H_2S_2O_8)` and `O_2` form in equimolar amount The amount of `H_2` that will form simultaneously will be (`2H_2SO_4 -> H_2S_2O_8 + 2H^+ + 2e^-`)

A

thrice that of `O_2` in moles

B

twice that of `O_2` in moles

C

equal to that of `O_2` in moles

D

half of that of `O_2` in moles

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