Q 2670556416.     Following cell has EMF 0.7995 V.

`Pt | H_2 (1 atm) | HNO_3(1M) || AgNO_3 (1M) |Ag`

If we add enough KCI to the Ag cell so that the final `Cl^-` is 1M Now the measured emf of the cell is 0.222 V.

The `K_(sp)` of AgCI would be

A

`1 xx 10^(-9.8)`

B

`1 xx 10 ^(-19.5)`

C

` 2 xx 10^(-10) `

D

`2.64 xx 10^(-14)`

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