Q 3010080819.     A man on the top of an observation tower finds an object at an angle of depression `30^{0}`. After the object was moved `30` metres in a straight line towards the tower, he finds the angle of depression to be `45^{0}`. The distance of the object now from the foot of the tower in metres is

A

`15\sqrt{3}`

B

`15(\sqrt{3}+1)`

C

`15(\sqrt{3}-1)`

D

`15(2+\sqrt{3})`

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