Q 3010891710.     An observer finds that the angular elevation of a tower is `\theta`. On advancing a metres towards the tower, the elevation is `45^{0}` and on advancing b metres nearer the elevation is `90^{0}-\theta`, then the height of the tower (in metres) is

A

`\frac{ab}{a+b}`

B

`\frac{ab}{a-b}`

C

`\frac{2ab}{a+b}`

D

` \frac{2ab}{a-b}`

Find instant solution to any question from our database of 1.5 Lakh + Questions

 

Access free resources including

Engineering

Medical

Banking

DEFENCE

SSC

RRB

CBSE-NCERT

OLYMPIAD

Today's Score

0
Success Rate: NAN %

Practice & Test

Sr. No.SubjectTagCorrectRecorded Answer