Q 3071112926.     A person observes the top of a tower from a point A on the ground. The elevation of the tower from this point is `60^{\circ}`. He moves `60\ m` in the direction perpendicular to the line joining A and base of the tower. The angle of elevation of the tower from the point is `45^{\circ}`. Then the height of the tower (in meters) is

A

`60\sqrt { \frac{3}{2} }`

B

`60\sqrt {2 }`

C

`60\sqrt {3 }`

D

`60\sqrt { \frac{2}{3} }`

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