Q 3080812717.     AB is a vertical pole with base at B. A man finds the angle of elevation of the point A from a certain point C on the ground is `60^{0} `. He move away from the pole along line BC to a point D such that `CD= 7` m , from D the angle of elevation of point A is `45^{0}` , then height of the pole is

A

`\frac{7\sqrt{3}}{2} ( \sqrt{3}+1 )`

B

`\frac{7\sqrt{3}}{2} ( \sqrt{3}-1 )`

C

`\frac{7\sqrt{3}}{2 ( \sqrt{3}+1 )}`

D

`\frac{7\sqrt{3}}{2 ( \sqrt{3}-1 )}`

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