Let `z_1 = x_1 + iy_1 = (x_1, y_1)` and `z_2 = x_2 + iy_2 = (x_2 , y_2),` where `x_1, y_1, x_2 , y_2 in R` and
`i = sqrt(-1)` , be two complex numbers.
If `anglePOQ = theta` , then from Coni method,
`(z_2-0)/(z_1-0) = |z_2|/|z_1| e^(i theta)`
`=> (z_2barz_1)/(z_1barz_1) = |z_2|/|z_1| e^(i theta) => (z_2barz_1)/|barz_1|^2 = |z_2|/|z_1|e^(i theta)`
`z_2barz_1 = |z_1| |z_2| e^(i theta)`
`z_2 barz_1 = |z_1| |z_2| (cos theta + i sin theta)`
`=> Re (z_2barz_1) = |z_1| |z_2|cos theta...............(i)`
and Im `(z_2barz_1)= |z_1||z_2| sin theta .............(ii)`
The dot product `z_1` and `z_2` is defined by,
`z_1·z_2 = | z_1|| z_2 | cos theta` `= Re (barz_1 z_2 ) = x_1x_2 + y_1y_2` [from Eq. (i)]
and cross product of `z_1` and `z_2` is defined by `z_1 xx z_2 =| z_1 || z_2| sin theta`
`= Im (barz_1z_2) = x_1y_z - x_zy_1` [from Eq. (ii)]
Hence, `z_1·z_2 = x_1x_2 + y_1y_2 = Re(barz_1z_2)` and `z_1 x z2 = x_1y_2 - x_2 y_1 = Im (barz_1z_2)`
`text(Fundas)`
1. If `z_1` and `z_2` are perpendicular, then `z_1 · z_2 = 0`
2. If `z_1` and `z_2` are parallel, then `z_1 xx z_2 = 0`
3. Projection of `z_1` on `z_2 = (z_1·z_2) /| z_2|`
4. Projection of `z_2` on `z_1 = (z_1·z_2)/|z_1 |`
5. Area of triangle, if two sides represented by `z_1` and `z_2` is `1/2 | z_1 xx z_2 |`.
6. Area of a parallelogram having sides `z_1` and `z_2` is `| z_1 xx z_2 |` .
7. Area of parallelogram, if diagonals represented by `z_1` and `z_2` is `1/2 | z_1 xx z_2 |`.
Let `z_1 = x_1 + iy_1 = (x_1, y_1)` and `z_2 = x_2 + iy_2 = (x_2 , y_2),` where `x_1, y_1, x_2 , y_2 in R` and
`i = sqrt(-1)` , be two complex numbers.
If `anglePOQ = theta` , then from Coni method,
`(z_2-0)/(z_1-0) = |z_2|/|z_1| e^(i theta)`
`=> (z_2barz_1)/(z_1barz_1) = |z_2|/|z_1| e^(i theta) => (z_2barz_1)/|barz_1|^2 = |z_2|/|z_1|e^(i theta)`
`z_2barz_1 = |z_1| |z_2| e^(i theta)`
`z_2 barz_1 = |z_1| |z_2| (cos theta + i sin theta)`
`=> Re (z_2barz_1) = |z_1| |z_2|cos theta...............(i)`
and Im `(z_2barz_1)= |z_1||z_2| sin theta .............(ii)`
The dot product `z_1` and `z_2` is defined by,
`z_1·z_2 = | z_1|| z_2 | cos theta` `= Re (barz_1 z_2 ) = x_1x_2 + y_1y_2` [from Eq. (i)]
and cross product of `z_1` and `z_2` is defined by `z_1 xx z_2 =| z_1 || z_2| sin theta`
`= Im (barz_1z_2) = x_1y_z - x_zy_1` [from Eq. (ii)]
Hence, `z_1·z_2 = x_1x_2 + y_1y_2 = Re(barz_1z_2)` and `z_1 x z2 = x_1y_2 - x_2 y_1 = Im (barz_1z_2)`
`text(Fundas)`
1. If `z_1` and `z_2` are perpendicular, then `z_1 · z_2 = 0`
2. If `z_1` and `z_2` are parallel, then `z_1 xx z_2 = 0`
3. Projection of `z_1` on `z_2 = (z_1·z_2) /| z_2|`
4. Projection of `z_2` on `z_1 = (z_1·z_2)/|z_1 |`
5. Area of triangle, if two sides represented by `z_1` and `z_2` is `1/2 | z_1 xx z_2 |`.
6. Area of a parallelogram having sides `z_1` and `z_2` is `| z_1 xx z_2 |` .
7. Area of parallelogram, if diagonals represented by `z_1` and `z_2` is `1/2 | z_1 xx z_2 |`.