Mathematics STRAIGHT LINE

CONDITION FOR THE LINES TO BE PARALLEL :

lfthe lines `a_1x + b_1y + c_1 = 0` and `a_2x + b_2y + c_2 = 0` are parallel, then
`m_1 =m_2`

`=> - a_1/b_1 = - a_2/b_2`

`=> a_1/a_2 = b_1/b_2`

CONDITON FOR THE LINES TO BE PERPENDICULAR

lfthe lines `a_1x + b_ 1y + c_1 = 0` and `a_2x + b_2y + c_2 = 0` are perpendicular, then

`m_1m_2 =-1` `=> (-a_1/b_1) xx ( - a_2/b_2) = -1`

`=> a_1 a_2 +b_1 b_2 =0`

lffollows from the above discussion that the lines `a_ 1x + b_1y+c_1 = 0` and `a_2x + b_2y+c_2 = 0` are

(1) Condition if `a_1/a_2 = b_1/b_2 = c_1/c_2`

(2) Parallel if `a_1/a_2 = b_1/b_2 ne c_1/c_2`

(3) Interesecting if `a_1/a_2 ne b_1/b_2`

(4) Perpendicular if `a_1a_2 +b_1b_2 =0`

EQUATION OF A LINE PARALLEL TO A GIVEN LINE

The equation of a line parallel to a given line `ax + by + c = 0` is
`ax+by+lambda = 0`
where `A` is a constant and value of `A` can be determined using another given condition

EQUATION OF A LINE PEREPENDICULAR TO A GIVEN LINE

The equation of a line perpendicular to a given line `ax+ by+ c = 0` is
`bx - ay+ lambda = 0`
where `A` is a constant and value of `A` can be determined using another given condition.

Distance Between Two Parallel Lines :

Let `(x_1 , y_1)` be any point on the line `ax + by +c_2 = 0`

Distance of point `(x_1, y_1)` from the line `ax+ by +c_1 = 0` is

`p=(|ax_1+by_1+c|)/(sqrt(a^2+b^2))`

Now point `(x_1, y_1)` lies on `ax + by+c_2 = 0` then

`ax_1 +by_1 +c_2 = 0`

`=> ax_1 + by_1 = -c_2`

`=> p=(|c_1-c_2|)/(sqrt(a^2+b^2))`

 
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