We are already familiar with the quadratic equations and have solved them in the set of real numbers in the cases where discriminant is non-negative, i.e.,` ≥ 0,`
Let us consider the following quadratic equation: `ax^2 + bx + c = 0` with real coefficients `a, b, c` and `a ≠ 0.`
Also, let us assume that the `b^2 - 4ac < 0.`

Now, we know that we can find the square root of negative real numbers in the set of complex numbers. Therefore, the solutions to the above equation are available in the set of complex numbers which are given by

`x=(-bpmsqrt(b^2-4ac))/(2a)=(-bpmisqrt(4ac-b^2))/(2a)`