Magnetic field (at large distances) due to current in a circular current loop is very similar in behavior to the electric field of an electric dipole. We know that the magnetic field on the axis of a circular loop, of a radius R,carrying a steady current I

`B = ((mu_0I) 2pi a^2)/(4pi(a^2 + x^2)^(3/2))`

its direction is along the axis and given by the right-hand thumb rule. Here, `x` is the distance along the axis from the centre of the loop.
For`x > > R,` we may drop the `R^2` term in the denominator. Thus

`B = 2(mu_0/(4pi)(IA)/x^3)`

Where `A=piR^2 =`area of the loop
The expression is very similar to an expression obtained earlier for the electric field of a dipole. The similarity may be seen if we can define the magnetic dipole moment `vecmu` as `vecmu = I vecA`

The direction of `vecmu ` is the same the area vector `vecA` The SI unit for the magnetic dipole moment is ampere-mete`r^2` (A.m^2)