Q 1129078811.     A steel wire of length `1 m`, mass `0.1` kg and uniform cross-sectional area `10^(–6) m^2` is rigidly fixed at both ends. The temperature of the wire is lowered by `20^°C` and transverse waves are set-up by plucking the string in the middle, calculate the frequency of the fundamental mode of vibration.
(Given: `Y_text(steel) = 2 × 10^11` N/`m^2`, `α_(steel )= 1.21 × 10^(–5)`/°C)

JEE 1984
A

`14` Hz

B

`13` Hz

C

`11` Hz

D

`17` Hz

HINT

Speed of transverse wave on the wire, `v = sqrt(T/μ)`

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