Q 1666323275.     The angular frequency of the damped oscillator is given by,

`\omega = \sqrt{ ( \frac{k}{m}- \frac{r^2}{4m^2} )} ` where `k` is the spring constant, `m` is the mass of the oscillator and ` r` is the damping constant. If the ratio `\frac{r^2}{mk}` is `80` %, the change in time period compared to the undamped oscillator is approximately as follows :

JEE 2014 Mains Paper 1
A

increases by `8%`

B

decreases by `8%`

C

increases by `1%`

D

decreases by `1%`

0
Success Rate: NAN %
Sr. No.SubjectTagCorrectRecorded Answer