Q .     A condenser of capacity `C` is charged to a potential difference of `V_1`. The plates of the condenser are then connected to an ideal inductor of inductance `L`. The current through the inductor when the potential difference across the condenser reduces to `V_2` is

AIPMT 2010
A

`( \frac{C(V_1 - V_2)^2}{L} )^{\frac{1}{2}}`

B

`\frac{C(V_1^2 - V_2^2 )}{L}`

C

`\frac{C(V_1^2 + V_2^2 )}{L}`

D

`( \frac{C(V_1^2 - V_2^2 )}{L} )^{\frac{1}{2}}`

Today's Score

0
Success Rate: NAN %

Practice & Test

Sr. No.SubjectTagCorrectRecorded Answer