Q 1154191054.     Let `omega` be a complex root of unity with `omega!= 1`. A fair die is thrown three times. If `r_1, r_2, r_3` are the numbers obtained on the die, the probability that `omega^(r_1) +omega^(r_2) + omega^(r_3) = 0` is

JEE 2010 Mains
A

`1/18`

B

`1/9`

C

`1/9`

D

`1/9`

HINT

Dstribute the numbers such that there is atleast one number from each of the `3` sets.

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