Q 1651801724.     Given that

`Zn^(2+)(aq) +2e^(-) -> Zn(s); E^(circ)_(red) =-0.76 V`
`Cr^3+(aq) +3e^(-) -> Cr(s) ; E^(circ)_(red) = -0.74 V`

Calculate the equilibrium constant `K` at `25^(circ)C`
for the following balanced reaction,

`3Zn(s) + 2Cr^3 + (aq) -> 3Zn^(2+) (aq) + 2Cr(s)`

GGSIPU 2015
A

`k =e^(-0.02)`

B

`k= e^(0.02)`

C

`k =e^(4.7)`

D

`k =e^(2.0)`

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